y^2-4y+15=6

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Solution for y^2-4y+15=6 equation:


Simplifying
y2 + -4y + 15 = 6

Reorder the terms:
15 + -4y + y2 = 6

Solving
15 + -4y + y2 = 6

Solving for variable 'y'.

Reorder the terms:
15 + -6 + -4y + y2 = 6 + -6

Combine like terms: 15 + -6 = 9
9 + -4y + y2 = 6 + -6

Combine like terms: 6 + -6 = 0
9 + -4y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + -4y + -9 + y2 = 0 + -9

Reorder the terms:
9 + -9 + -4y + y2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4y + y2 = 0 + -9
-4y + y2 = 0 + -9

Combine like terms: 0 + -9 = -9
-4y + y2 = -9

The y term is -4y.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4y + 4 + y2 = -9 + 4

Reorder the terms:
4 + -4y + y2 = -9 + 4

Combine like terms: -9 + 4 = -5
4 + -4y + y2 = -5

Factor a perfect square on the left side:
(y + -2)(y + -2) = -5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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